Practice
Grade 8 Building the Cylinder Volume Formula: Graded Practice Set
This Grade 8 practice-set record develops fluency with building the cylinder volume formula from layered-circle and base-area-times-height reasoning. It is designed for independent practice after the linked derivation and formula-use records, so it focuses on reconstruction, interpretation, unit control, and reverse reasoning rather than re-teaching the full lesson.
Position in the topic
Use this record after the linked practice sets on cylinder-volume derivation and formula use:
- [rea.m08.geometry-measurement.volume.cylinder-volume-derivation-practice-set]
- [rea.m08.geometry-measurement.volume.cylinder-volume-formulas.practice-set]
- [rea.m08.geometry-measurement.volume.basic-formulas.formula-selection.practice-set]
- [rea.m08.geometry-measurement.volume.basic-formulas.practice-set]
This set is narrower: it concentrates on building the formula V = pi r^2 h from structure.
What this set practices
- seeing a cylinder as many equal circular layers
- identifying the base area as
pi r^2 - expressing volume as
base area x height - distinguishing radius from diameter
- deciding when an answer should stay exact and when to approximate
- reverse reasoning about missing dimensions
Quick method reminder
Do not re-study the full lesson here; use the linked records for that. For this set, the working idea is:
- Find the area of one circular base.
- Multiply by the height.
- Keep units cubic.
So for a cylinder,
V = Bh = (pi r^2)h = pi r^2 h.
Difficulty tags
D1straightforward identification or substitutionD2multi-step setup with unit careD3reverse or comparison reasoningD4explanation or non-routine derivation reasoning
Problems
A. Building the formula from structure
-
D1A cylinder is made of circular layers. Each layer has area20 cm^2, and the height is9 cm. What is the volume? -
D1A cylinder has base area13 pi m^2and height4 m. Write its volume in exact form. -
D1A cylinder has radius3 cmand height8 cm. Build the volume formula step by step and find the exact volume. -
D1A cylinder has diameter10 cmand height7 cm. Build the formula carefully and find the exact volume. -
D1A cylinder has radius1.5 mand height12 m. Write the exact volume in terms ofpi. -
D2The base of a cylinder has area49 pi cm^2. What is the radius of the base? -
D2The base area of a cylinder is81 pi mm^2, and the height is11 mm. Find the exact volume. -
D2A cylinder has radius6 cm. If its height doubles, how does the volume change?
B. From circles to cylinders
-
D2A circular base has radius4 cm. Find the base area, then use height15 cmto find the cylinder volume in exact form. -
D2A cylinder has diameter14 mand height5 m. Find the exact volume. -
D2A soup can is modeled as a cylinder with radius3.5 cmand height10 cm. Find the volume to the nearest tenth of a cubic centimetre. -
D2A cylinder has radius9 mmand volume729 pi mm^3. Find its height. -
D2A cylinder has height20 cmand exact volume500 pi cm^3. Find its radius. -
D3Two cylinders have the same height. Cylinder A has radius2 cm. Cylinder B has radius5 cm. How many times the volume of A is the volume of B? -
D3Two cylinders have the same radius. Cylinder P has height7 cm. Cylinder Q has height21 cm. Compare their volumes. -
D3A cylinder has radius4 cmand height10 cm. Another has radius8 cmand height10 cm. Compare the volumes and explain briefly.
C. Reverse and reasoning problems
-
D3A cylinder has exact volume432 pi cm^3and height12 cm. Find the radius. -
D3A cylinder has exact volume300 pi m^3and radius5 m. Find the height. -
D3A cylinder has diameter16 cmand volume768 pi cm^3. Find the height. -
D4A student says, “If the radius doubles, the volume doubles.” Give a counterexample using a fixed height of6 cm, starting from radius2 cm. -
D4A cylinder and a prism both have height9 cmand base area24 cm^2. Compare their volumes and explain what this shows aboutV = Bh. -
D4A cylinder has radiusrand heighth. Another has radius2rand heighth/2. Compare their volumes algebraically. -
D4A cylinder has exact volume980 pi cm^3. One possible height is5 cm. Find the corresponding radius. Then find a different whole-number height that gives a different rational radius. -
D4A cylindrical water container has inside diameter12 cmand inside height18 cm. It is filled to half its height. Find the amount of water in exact form and to the nearest tenth. Explain why halving the height halves the volume here.
Answer key
180 cm^352 pi m^372 pi cm^3175 pi cm^327 pi m^37 cm891 pi mm^3- The volume doubles.
- Base area
16 pi cm^2; volume240 pi cm^3 245 pi m^3384.8 cm^3approximately9 mm5 cm- Cylinder B has
25/4times the volume of Cylinder A. - Cylinder Q has
3times the volume of Cylinder P. - The second cylinder has
4times the volume. 6 cm12 m12 cm- Original volume
24 pi cm^3; new volume96 pi cm^3; volume becomes4times as large, not2times. - They have equal volumes:
216 cm^3each. This shows volume depends on base area and height, not the base shape by itself. - The second volume is
2times the first. - For height
5 cm, radius14 cm. Example of another whole-number height:20 cm, giving radius7 cm. - Exact volume
648 pi cm^3; approximate volume2035.8 cm^3; halving the height halvesBhbecause the base area stays constant.
Full solutions for the hardest third
17. Exact volume 432 pi cm^3, height 12 cm
Use V = pi r^2 h.
432 pi = pi r^2 (12)
Divide both sides by 12 pi:
r^2 = 432/12 = 36
r = sqrt(36) = 6
So the radius is 6 cm.
18. Exact volume 300 pi m^3, radius 5 m
Start with V = pi r^2 h.
300 pi = pi (5^2) h
300 pi = 25 pi h
Divide by 25 pi:
h = 300/25 = 12
So the height is 12 m.
19. Diameter 16 cm, volume 768 pi cm^3
The radius is half the diameter:
r = 16/2 = 8 cm
Now use V = pi r^2 h:
768 pi = pi (8^2) h
768 pi = 64 pi h
Divide by 64 pi:
h = 768/64 = 12
So the height is 12 cm.
20. Counterexample to “If the radius doubles, the volume doubles.”
Keep height fixed at 6 cm.
First cylinder: r = 2 cm
V = pi r^2 h = pi (2^2)(6) = 24 pi cm^3
Second cylinder: radius doubles to 4 cm
V = pi (4^2)(6) = 96 pi cm^3
Compare:
96 pi / 24 pi = 4
So doubling the radius makes the volume 4 times as large, not 2 times as large, when height stays the same. The reason is that radius is squared in pi r^2 h.
21. Cylinder and prism with the same base area and height
Both solids have:
- base area
24 cm^2 - height
9 cm
Use V = Bh for each solid:
V = 24 x 9 = 216 cm^3
So both volumes are 216 cm^3.
This shows that volume can be built from the same structure, base area x height, even when the base shapes are different. For a cylinder, the base happens to be a circle, so B = pi r^2.
22. Compare a cylinder with radius r, height h to one with radius 2r, height h/2
First cylinder:
V1 = pi r^2 h
Second cylinder:
V2 = pi (2r)^2 (h/2)
Simplify:
V2 = pi (4r^2)(h/2)
V2 = 2 pi r^2 h
Since V1 = pi r^2 h,
V2 = 2V1
So the second cylinder has twice the volume of the first.
23. Exact volume 980 pi cm^3
First, use height 5 cm.
980 pi = pi r^2 (5)
Divide by 5 pi:
r^2 = 980/5 = 196
r = sqrt(196) = 14
So if the height is 5 cm, the radius is 14 cm.
Now find a different whole-number height that gives a different rational radius. We want 980/h to be a perfect square or at least a rational square. Choose h = 20.
Then:
r^2 = 980/20 = 49
r = 7
So another valid choice is height 20 cm with radius 7 cm.
24. Half-filled cylindrical container
Inside diameter 12 cm means radius 6 cm.
The full height is 18 cm, so half-filled means water height 9 cm.
Use V = pi r^2 h:
V = pi (6^2)(9)
V = pi (36)(9)
V = 324 pi
Check carefully: that is the volume for height 9 cm, and since 36 x 9 = 324, the water volume is 324 pi cm^3.
Now approximate:
324 pi ≈ 1017.9 cm^3
Why does halving the height halve the volume? Because for a cylinder with fixed radius, the base area pi r^2 stays constant, so volume is directly proportional to height:
V = (constant) x h
If height is cut in half, volume is cut in half.
Correction note for Problem 24
If the cylinder were filled to half its full volume, that would be 648 pi cm^3. But the problem states it is filled to half its height, so the correct water volume is 324 pi cm^3 ≈ 1017.9 cm^3.
Common mistakes and repairs
-
Using diameter in place of radius. Repair: mark
r = d/2before substituting. -
Forgetting to square the radius. Repair: write the base area separately first:
B = pi r^2. -
Writing square units instead of cubic units. Repair: area is square units; volume is cubic units.
-
Thinking every dimension change affects volume the same way. Repair: height changes volume linearly, but radius changes volume quadratically.
-
Converting exact answers to decimals too early. Repair: keep
piuntil the last step unless the question asks for an approximation.
Short self-check
You are ready to move on if you can do all of these without prompting:
- explain why
V = Bhworks for cylinders - replace
Bwithpi r^2 - switch correctly between radius and diameter
- solve for a missing height or radius from an exact volume
- explain how volume changes when radius or height changes